(5-x^2)(x^3-5x+4)=0

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Solution for (5-x^2)(x^3-5x+4)=0 equation: 


Simplifying
(5 + -1x2)(x3 + -5x + 4) = 0

Reorder the terms:
(5 + -1x2)(4 + -5x + x3) = 0

Multiply (5 + -1x2) * (4 + -5x + x3)
(5(4 + -5x + x3) + -1x2 * (4 + -5x + x3)) = 0
((4 * 5 + -5x * 5 + x3 * 5) + -1x2 * (4 + -5x + x3)) = 0
((20 + -25x + 5x3) + -1x2 * (4 + -5x + x3)) = 0
(20 + -25x + 5x3 + (4 * -1x2 + -5x * -1x2 + x3 * -1x2)) = 0
(20 + -25x + 5x3 + (-4x2 + 5x3 + -1x5)) = 0

Reorder the terms:
(20 + -25x + -4x2 + 5x3 + 5x3 + -1x5) = 0

Combine like terms: 5x3 + 5x3 = 10x3
(20 + -25x + -4x2 + 10x3 + -1x5) = 0

Solving
20 + -25x + -4x2 + 10x3 + -1x5 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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